Q3. A body of mass 10 kg is moving with a velocity of 1 m/s2. Find () The
magnitude of the force required to stop the body in 10 sec (ii) The distance the
body will move through before coming to rest
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PHYSICS
A body of mass 10 Kg is moved with a uniform speed on a rough horizontal surface, for a distance of 2 m. The work done is 150 J. The surface is inclined to the horizontal at 30. The same body is moved over the inclined plane for a distance of 2 m. The work done against friction will be: (Take g=10 ms−
2):
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ANSWER
Given,
Mass M=10kg
Work done, W=150J
Displcement on horizontal = displacement on incline =d=2m
Friction force on horizontal plane,F
r =μmg
Friction force on incline plane,F
r′ =μmgcosθ
Speed is uniform means net acting force is equal to friction force
Work done,W=F r .d=μmg.d⇒μ= mg.d
W = 10×10×2150 =0.75
Work done on incline plane, W=F r,d=μmgcosθ.d⇒W=0.75×10×10×cos30 o ×2 ⇒W=75 3 J
Work done against friction is 75 3J