Q3 A car moving with a speed of 72kmph applies brakes for 5 seconds. After 5 seconds, these
of the car 18 kmph, Calculate the acceleration of the car.
Answers
Answered by
50
✬ Acceleration = –3 m/s² ✬
Explanation:
Given:
- Initial velocity of car is 72 km/h.
- Time given is 5 seconds.
- Final velocity of car is 18 km/h.
To Find:
- What is acceleration of car ?
Formula to be used:
- v = u + at (first law of motion)
Solution: First of all convert the km/h to m/s. To convert multiply the speed by 5/18.
➨ Initial velocity = 72 × 5/18 = 4 × 5 = 20 m/s.
➨ Final velocity = 18 × 5/18 = 1 × 5 = 5 m/s.
Now we have
- u = 20 m/s.
- v = 5 m/s.
- t = 5 s
Putting all the values on formula
v = u + at
5 = 20 + a × 5
5 – 20 = 5a
–15 = 5a
–15/5 = a
–3 = a
Hence, the acceleration of car is –3 m/s².
- The rate of change of velocity is called acceleration. It is denoted by a.
- The velocity at which motion starts is termed as initial velocity. It is denote by u.
- The last velocity of an object after a period of time. It is denoted by v.
- v = ut + 1/2at² ( Second law of motion)
- v² = u² + 2as ( Third law of motion )
amitkumar44481:
Great :-)
Answered by
58
- A car is moving with a speed = 72 km/h
- It applies brakes for 5s .
- After 5s the speed of the car = 18 km/h
- Acceleration of the car .
According to the question,
- Initial velocity (u) = 72 km/h = 20 m/s
- Time (t) = 5 s
- Final velocity (v) = 18 km/h = 5 m/s
[Note :- -ve sign indicates that the car is in deaccelerating motion .]
The acceleration of the car is “ 3 m/s² ”
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