Question

Q3: A current of 1A is drawn by a filament of an electric bulb find the number of electrons pas
through a cross-section of the filament in 16 seconds?
Q4: An electric bulb draws a current of 0.25 A for 20 minutes calculates the amount of electric
charge that flows through a circuit.
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Answer 1

Answer:

Q.3. 10²⁰ electrons

Q.4. 300 C

Explanation:

Q3. I = 1A, t = 16s, charge on 1 electron (e) = 1.6 * 10⁻¹⁹ C, no. of electrons (n) = ?

We know that Q = ne

and also that I = Q/t

So, we get I = ne/t

or, n = It/e = (1 * 16)/(1.6 * 10⁻¹⁹) = 10²⁰ electrons

Q.4. I = 0.25A, t = 20 min = 20*60 = 1200 s, Q=?

I = Q/t

So, Q = It = 0.25 * 1200 = 1200/4 = 300 C