Question

Q3. A mountaineer shouts for help. Half a second later she hears the echo. How
far away is the rock which is reflecting her voice? (Speed of sound in air
330m/s)...
plz explain with steps​

Answer 1

Given

Time = 1/2 sec = 0.5 s

Time = 1/2 sec = 0.5 sSpeed = 330 m/s

We Have to Find Distance

As, we know

Distance = Speed × Time

Substituting the Values

➱ 330 × 0.5

➱ 165 m

Distance Between Mountainer & rock = Distance Travelled By Sound/2

➱ 165/2

➱ 82.5m

Therefore, the sound was reflected to 82.5m far

Additional Information

What is Echo?

➥ Echo is defined as a Sound which is heard after the reflection of Sound from a Surface.

What is Reverberation

➥ Reverberation is defined as the repetitive sound which results in persistence of Sound in big balls.

What is Sound

➥ Sound is a form of Energy, and also a wave i.e Mechanical Wave.

Answer 2

82.5 m

Explanation:

Time = 1/2 sec

        = 0.5 sec

Speed of the sound = 330 m/sec

=> Distance = Speed x Time

                    = 330 x 0.5 m

                    = 165 m

(Distance between mountain and rock = Distance traveled by the sound)/2

=> 165/2 m

=> 82.5 m ans.

Hope it helps you.....