Question

Q3. A race scooter is seen accelerating uniformly from 18.5 m/s to 46.1 m/s in 2.47 seconds. Determine the
acceleration of the scooter and the distance travelled.

Please answer step by step.​

Answer 1

Answer:

a=rate of change in velocity/time taken

a=46.1-18.5/2.47=11.17ms^2

Distance=v^2=u^2+2as

46.1^2=18.5^2+2(11.17)s

2125.21-342.25/22.3=s

S=79.95m