Question

Q3. A ribbon is (3x+4)m long. Another ribbon of length (2x-7)m is attached to it. What is the total length of the
two ribbons? (2 marks)
Soln.-​

Answer 1

Answer:

Given,

length of wire =(7x−3)m

and wire cut for use has length =(3x−4)m

Left wire =(7x−3)−(3x−4)=(4x+1)m

(b) Left wire =(4x+1)m

Perimeter of equilateral triangle = Length of wire left

⇒ 3×side=4x+1

⇒ side=

3

(4x+1)

=

3

1

(4x+1)m

Answer 2

Answer:

2x

Step-by-step explanation:

3+4-7x

2-7-(-5x)

7x+(-5x)

7x-5x

2x