Q3.A solid rectangular piece of iron measures 1.05 m X 70 cm X 1.5 cm. Find the weight of this piece in Kilograms if 1cm3 of iron weighs 8 grams.
Answers
Answered by
447
Hi,
Shape of a rectangular solid is
cuboid,
Dimensions of the cubiod is
Length = l = 1.05 m
l = 1.05 × 100 cm = 105 cm
Breadth = b = 70 cm
Height = h = 1.5 cm
Volume of the solid = lbh
V = 105 cm × 70cm × 1.5 cm
V = 11025 cm³
According to the problem given,
1 cm³ iron weighs 8 grams
11025 cm³ iron weighs = 8 ×11025 gm
= 88200grams
= 88200/1000kg
=88.2kgs
Therefore,
Solid weighs 88.2 kgs
I hope this helps you.
:)
Shape of a rectangular solid is
cuboid,
Dimensions of the cubiod is
Length = l = 1.05 m
l = 1.05 × 100 cm = 105 cm
Breadth = b = 70 cm
Height = h = 1.5 cm
Volume of the solid = lbh
V = 105 cm × 70cm × 1.5 cm
V = 11025 cm³
According to the problem given,
1 cm³ iron weighs 8 grams
11025 cm³ iron weighs = 8 ×11025 gm
= 88200grams
= 88200/1000kg
=88.2kgs
Therefore,
Solid weighs 88.2 kgs
I hope this helps you.
:)
Answered by
116
Solution :
Length = 1.05 m = 105 cm
Breadth = 70 cm
Height = 1.5 cm
Volume : length X breadth X height
= ( 105 X 70 X 1.5 ) cm^3
= 11025 cm^3
1 cm^3 = 8 grams
=> 11025 X8
= 88200 grams
= 88.2 kg
Length = 1.05 m = 105 cm
Breadth = 70 cm
Height = 1.5 cm
Volume : length X breadth X height
= ( 105 X 70 X 1.5 ) cm^3
= 11025 cm^3
1 cm^3 = 8 grams
=> 11025 X8
= 88200 grams
= 88.2 kg
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