Question

Q3. A taxi fare in a city is such that Rs 20 is the fixed amount
and Rs 10 per km is charged. Taking the distance covered as x
km and total fare as Rs y, write a linear equation and also
draw the graph of the same.

Answer 1

Answer:

20 + 10x = y

Step-by-step explanation:

20 is fixed.

10 per km so for x km it will be 10x

y is total as per question.

so,

fixed amount plus amount of km travelled will be total.

so,

20+10x=y

Answer 2

Answer:

 x0 12 y38 13 

Taxi fare for first kilometer = Rs. 8

Taxi fare for subsequent distance = Rs. 5

Total distance covered =x

Total fare =y

Since the fare for first kilometer = Rs.8

According to problem,

Fare for (x–1) kilometer = 5(x−1)

So, the total fare y=5(x−1)+8

⇒y=5(x−1)+8

⇒y=5x–5+8

⇒y=5x+3

Hence, y=5x+3 is the required linear equation.

Now the equation is

y=5x+3    ...(1)

Now, putting the value x=0 in (1)

y=5×0+3

y=0+3=3 So the solution is (0,3)

Putting the value x=1 in (1)

y=5×1+3

y=5+3=8. So the solution is (1,8)

Putting the value x=2 in (1)

y=5×2+3

y=10+3=13. So the solution is (2,13)