Question

Q3. A train covered a certain distance at a uniform speed. If the train had been 30 km/hr faster, it would have taken 2 hours less than the scheduled time. If the train were slower by 15 km/hr, it would have taken 2 hours more than the scheduled time. Find the length of the journey. bou ure to do an km down the stream and it returns in 4 hours. Find the speed​

Answer 1

Answer:

The actual speed of the train be x km/hr and

The scheduled time be y hours.

Then,

The distance of the journey = speed x time =xy

According to the question, we have

(x+30)(y−2)=xy

⇒xy=2x+30y−60=xy

⇒−2x+30y=60 … (i)

And,

(x=15)(y+2)=xy

⇒xy−15y+2x−30=xy

⇒2x−15y=30 … (ii)

Adding equations (i) and (ii), we have

15y=90

⇒y=

15

90

⇒y=6

On substituting the value of y in equation (i), we have

−2x+30(6)=60

⇒−2x+180=60

⇒−2x=60−180=−120

⇒x=

−2

−120

⇒x=60

Therefore, the distance of the journey =60×6=360 km.

Answer 2

Answer:

Time taken. Speed

2 30

4. x

then x=2/4 * 30/x

then cross multiply...