Question

Q3) An object executing SHM is at its maximum displacement from its equilibrium position which of the following is maximum at that position
Acceleration b) velocity c)kinetic energy d) none of these​

Answer 1

At either position of maximum displacement, the force is greatest and is directed toward the equilibrium position, the velocity (v) of the mass is zero, its acceleration is at a maximum, and the mass changes direction.

Answer 2

Answer:

(a) Acceleration of object executing SHM would be maximum at maximum displacement.

Explanation:

Step by step solution:

Step 1: Prerequisite knowledge

A particle executing SHM is represented by the equation $x=A\sin\omega t$

The velocity of the particle is represented by $v=\omega\sqrt{(A^{2}-x^{2} ) }$

The acceleration is represented by $a=-\omega^{2}x$

The KE is represented by $KE= \frac{1}{2} m\omega^{2} (A^{2}-x^{2} )$

Step 2: Putting x= A

For maximum displacement x=A

Putting in the given above equations in step 1, we get

v=0

KE= 0

$a=-\omega^{2}A$

which is maximum acceleration in opposite direction ( that is towards Equilibrium ).

Hence, option a is correct.