Q3. Calculate the kinetic energy, If a body of mass 3m is placed over the body of mass m and the velocity of the combination reduces to v/2.
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Answer:
The velocity of m kg=16 ms−1
and let the velocity of 2 m kg mass=v2ms−1
By the law of conservation of momentum
m×16=2m×v2
v2=8 ms−1
∴ Kinetic energy of the system
=21m(16)2+21(2m)(8)2=192 mJ.
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