Question

Q3. Calculate the no. of ions present in 51gm of Al2O3.
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Answer 1

Answer:

Now, 27 g of aluminium has ions = 6.022 × 10^23 aluminium ions. So, 0.027 g of aluminium has ions = 6.022 × 10^23 / 27 × 0.027. Thus, the number of aluminium ions (Al³+) in 0.051 gram of aluminium oxide is 6.022 × 10^20.

Answer 2

Answer:

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