Q3. Calculate the no. of ions present in 51gm of Al2O3.
plz give answer fast.
Answers
Answered by
1
Answer:
Now, 27 g of aluminium has ions = 6.022 × 10^23 aluminium ions. So, 0.027 g of aluminium has ions = 6.022 × 10^23 / 27 × 0.027. Thus, the number of aluminium ions (Al³+) in 0.051 gram of aluminium oxide is 6.022 × 10^20.
Answered by
2
Answer:
foll.ow me army
thn you can ans my questions
Similar questions