Question

Q3. Find a quadratic polynomial in y whose sum of the zeros is 6 and the product
is 6​

Answer 1

Answer:

The required equation is given by :

x² - ( Sum of the zeroes) x + ( Product of the Zeros) =0

⟹ x² - 6x +6 = 0

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Answer 2

Answer:

$y ^{2} - 6y + 6$

Step-by-step explanation:

alpha+beta=6(sum of zeros)

and, alpha*beta=6(product of zeros)

we know that,

quadratic polynomial=

$x {}^{2} - (sum \: of \: zeros)x + (product \: of \: zeros)$