Question

Q3
Find the area
the triangle whose
Sides measure 10 cm, 17 cm and 21 cm. also,
determine the length of the altitude on the side
which measure 17 cm?​

Answer 1

Answer:

Use formula √s(s-a)(s-b)(s-c) where s = 10+17+21/2 or

by finding altitude and using 1/2× base × height

Answer 2

Answer:

84cm$^2$

Step-by-step explanation:

We have  

AB=10cm

BC=21cm

CA=17cm

Now,

s=21+17+10/2

​ =  48/2 = 24

​then

Area of ΔABC=$\sqrt{ s(s-a)(s-b)(s-c)$

​ = $\sqrt{24(24-21)(24-17)(24-10)$

 =  24×3×7×14

​ =$84cm^{2}$