Question

Q3)Find the square of 912 by diagonal method.​

Answer 1

hi dear

your answer is

Complete step by step answer:

The diagonal method for finding the square of a number is described as follows,

(i) We form a square block having the rows and columns equal to the digit of the number.

(ii) We divide these smaller squares using diagonals and label the rows and columns with the digits of the number.

(iii) Then we multiply each row label with each column label and write the product in the smaller squares such that the tens digit is above the diagonal and the units digit is below the diagonal.

(iv) Then we add the digits in the sections created by the diagonals starting from the bottom right, and carry over the tens place digit (if any) to the section above it.

The number obtained at the end of this method is the square of the given number.

The given number is 98. It has two digits, so our block looks like the following,

Now, performing the multiplications, we get the following,

Next, we have to add the digits in the diagonal sections starting from the right bottom and carry over the tens place digit, if there is any, to the next section.

So, we get the units place as 4, since it is a single digit. Then in the second section, the addition is 2+6+2=102+6+2=10. So we get the tens place as 0 and we carry over the 1 to the next section. Then we have 1+7+1+7=161+7+1+7=16. So, the hundreds place digit is 6 and we carry over the 1 to the next section. Next, we have 1+8=91+8=9. So, 9 is the thousand place digit. Hence, the number obtained as the square of 98 is 9604.

hopes its helps you

Answer 2

Answer:

square of

Step-by-step explanation:

98 is 9604

hope it helps you