Question

Q3 Find the value of acceleration due to gravity on a planet whose diameter is 4 times of earth

Answer 1

Answer:

4 times that of earth

Explanation:

Use g=GM/R²

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Answer 2

Answer:

=> $39.2m/s^2$

Explanation:

As per the data given in the question, we have to find the value of acceleration

Assume that m is the mass of the earth

Mass = $4m$

And R be the radius of the earth,

We know that on the earth's surface, the acceleration due to gravity is given by:

$=> g_e=\frac{Gm}{R^2}$

Here, x is the acceleration of earth,

$=> g_x=\frac{G(4m)}{R^2}\\\\=> g_x=4\times \frac{G(4m)}{R^2}\\=> g_x=4\times g_e$

Now, $g_e=9.8m/s^2$

$g_x=4\times 9.8m/s^2$

$g_x=39.2m/s^2$

Hence, the value of acceleration is $39.2m/s^2$