Question

Q3. Find two solutions for each linear equation
(a) x + 2y =6​

Answer 1

Answer:

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Answer 2

QUESTION :- Find two solutions for x + 2y =6 linear equation

SOLUTION :-

The given equation is $\sf \fbox \blue{x+2y=6}$ ------------❶

• Putting $\sf x=0$ in equation ❶, we get

⇒ $\sf 0+2y=6$

⇒ $\sf 2y=6$

⇒ $\sf y=3$

$\sf \fbox \green{(0,3)}$ is a solution.

• Putting $\sf \fbox \blue{y=0}$ in equation ❶, we get

⇒ $\sf x+2×0=6$

⇒ $\sf {x=6}$

$\sf \fbox \green{(6,0)}$ is a solution.

• Putting $\sf \fbox \blue{x=2}$ in equation ❶, we get

⇒ $\sf 2+2y=6$

⇒ $\sf 2y=6 - 2$

⇒ $\sf 2y=4$

⇒ $\sf y=2$

$\sf \fbox \green{(2,2)}$ is a solution.

• Putting $\sf \fbox \blue{x=4}$ in equation ❶, we get

⇒ $\sf 4+2y=6$

⇒ $\sf 2y=2$

⇒ $\sf y=1$

$\sf \fbox \green{(4,1)}$ is a solution.

Hence, $\sf \fbox \orange{(0,3),(6,0),(2,2) \: and \: (4,1)}$ are four solutions of given equation.

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