Question

Q3. Five years ago, Anu was thrice as old as Sonu. Ten years later, Anu will be twice as old as Sonu.
How old are Anu and Sonu?​

Answer 1

Answer:-

Let the age of Anu be x years and Sonu be y years.

5 Years Ago,

Age of Anu = x - 5 years

Age of Sonu = y - 5 years

A.T.Q.

( x - 5) = 3(y-5)

= x = 3y - 15 + 5

= x = 3y - 10 _______________(1)

Ten Years Later,

Age of Anu = x + 10 years

Age of Sonu = y + 10 years

A.T.Q.

( x + 10) = 2(y + 10)

= 3y - 10 + 10 = 2y + 20

= 3y - 2y = 20

= y = 20

Substituting ( y = 20) in eq(1).

= x = 3y - 10

= x = 60 - 10

= x = 50

Hence,

Anu's age = x = 50 years

Sonu's age = y = 20 years.

Answer 2

$\huge \boxed{ \underline{ \underline{ \bf{Answer}}}}$

Given : √ Five years ago,

                Anu was thrice as old as Sonu.  

            √ And Ten years later,

              Anu will be twice as old as Sonu.

To find : √ The age of Anu and the Sonu.

Now, let us assumed that :-

Present ages :-

Anu = "x" year old

and

Sonu = "y" year old

Than, Five years ago :-

Age of Anu =  x – 5 years

Age of Sonu = y – 5 years

Anu was thrice as old as Sonu :-

x- 5  =  3(y – 5)

x – 5  =  3y – 15

x – 3 y  = - 10                        ………..   ( 1 )

Now 10 years later the ages are :-

Age of Anu =  x + 10

Age of Sonu = y + 10

According to given condition, we have

(x+10)=2(y+10)

x+10=2y+20

⇒x−2y=10                               --------    ( 2 )

Now, Subtracting equation (1) from (2), we get

y = 10−(−10)

y = 20 years

Then put the value of "y" in the 1st equation for getting the value of "x" :-

x − 3 ( 20 ) = −10

x − 60 = −10

x = 50 years

Atlast, i am going to conclude my whole answer :-

$\implies \boxed{\mathsf{Age\:of\:Anu\:=\:50\:years}}$

$\implies \boxed{\mathsf{Age\:of\:Sonu\:=\:20\:years}}$