Q3.Given that ABC is an equilateral triangle and BDC is an isosceles right triangle,right angled at D, with a common base BC.Find the measure of ABD.
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Given, ABC is an equilateral
BDC is an isosceles right triangle
angle CBD = angle BCD = x ( angles of isosceles triangle)
In triangle BDC
x + x + angle D = 180 ( angle sum property)
2x = 180 - 90
x = 90/2
x = 45
IN triangle ABC
angle ABC = 60 ( angles of an equilateral are equal to 60)
angle ABD = x + angle ABC
Angle ABD = 45+60
Angle ABD = 105
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Step-by-step explanation:
you can angle BCD and angle CBD by taking each as x and by angle sum property
ANGLE OF EQUILATERAL TRIANGLE IS EACH 60 DEGREE .
Then u can add angle CBD and angle ABC so your answer is 105
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