Math, asked by Sbchobi4401, 1 year ago

Q3.Given that ABC is an equilateral triangle and BDC is an isosceles right triangle,right angled at D, with a common base BC.Find the measure of  ABD.

Answers

Answered by ansh2014chauhan
157

Given, ABC is an equilateral

BDC is an isosceles right triangle

angle CBD = angle BCD = x ( angles of isosceles triangle)

In triangle BDC

x + x + angle D = 180 ( angle sum property)

2x = 180 - 90

x = 90/2

x = 45

IN triangle ABC

angle ABC = 60 ( angles of an equilateral are equal to 60)

angle ABD = x + angle ABC

Angle ABD = 45+60

Angle ABD = 105

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Answered by nikhilkumar729
6

Step-by-step explanation:

you can angle BCD and angle CBD by taking each as x and by angle sum property

ANGLE OF EQUILATERAL TRIANGLE IS EACH 60 DEGREE .

Then u can add angle CBD and angle ABC so your answer is 105

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