Question

Q3) if 1 is a zero of the polynomial p(x) = ax³ - 3 (a - 1) x- 1. then find the value of a.​

Answer 1

Answer:

'a' value is -2.

Step-by-step explanation:

Given polynomial is

p(x) = ax³-3(a-1)x-1

Now consider,

p(1) = a(1)³-3(a-1)(1)-1

= a(1) - 3(a-1)(1) - 1

= a - 3a - 3 - 1

= -2a - 4

4 = -2a

4/-2 = a

-2 = a

:. a = -2.

Hope it helps you.