Question

Q3. If 4 and -2 are the zeros of the Polynomial P(x) then P(x) is
a) x2 - 2x + 8
b) x2 - 2x - 8
c) x² + 2x -- 8
d) x2 + 2x + 8​

Answer 1

Answer:

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Step-by-step explanation:

B. X2-2x - 8....

Answer 2

Answer is b) x2 - 2x - 8

Because if we put both 4 and -2 in p(x)

So, In a) x2 - 2x + 8
P(4) = (4)2 - 2(4) + 8
= 16 - 8 + 8
= 16 ( doesn't equal to 0)
P(-2) = (-2)2 - 2(-2) + 8
= 4 + 4 + 8
= 8 + 8
= 16 ( doesn't equal to 0)


Similarly if we put in option b) x2 - 2x- 8

It will be,
P(4) = (4)2 - 2(4) - 8
= 16 - 8 - 8
= 16 - 16
= 0
P(-2) = (-2)2 - 2(-2) - 8
= 4 + 4 - 8
= 8 - 8
= 0
In option b) it will be 0

So, In this way if we put 4 and -2 in all options it will not be 0
But if we put in option b) it will be 0 so answer is option b) x2 - 2x- 8

Hope it will help you!!!!

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