Q3. If α and β are zeroes of a quadratic polynomial x2+4x+3, form the polynomial whose zeroes are 1+αβand1+βα.
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Hi !
p(x) = x² + 4x + 3
a = 1
b = 4
c = 3
α and β are zeros of p(x)
sum of zeros = α + β = -b/a = -4
product of zeros = αβ = c/a = 3
α + β = -4
αβ = 3
=========================
given ,
1 + αβ and 1 +βα are zeros of a polynomial
sum of zeros = 1 + αβ + 1 +βα
= 2 + 2αβ
= 2 + 2 × 3
= 8
product of zeros = (1 + αβ ) (1 +βα )
= 1 + αβ + αβ + α²β²
= 1 + 2αβ + (αβ)²
= 1 + 2 × 3 + (3)²
= 1 + 6 + 9
= 16
a quadratic polynomial can be formed:-
x² - (sum of zeros)x + (product of zeros)
= x² - 8x + 16 ---> required polynomial
p(x) = x² + 4x + 3
a = 1
b = 4
c = 3
α and β are zeros of p(x)
sum of zeros = α + β = -b/a = -4
product of zeros = αβ = c/a = 3
α + β = -4
αβ = 3
=========================
given ,
1 + αβ and 1 +βα are zeros of a polynomial
sum of zeros = 1 + αβ + 1 +βα
= 2 + 2αβ
= 2 + 2 × 3
= 8
product of zeros = (1 + αβ ) (1 +βα )
= 1 + αβ + αβ + α²β²
= 1 + 2αβ + (αβ)²
= 1 + 2 × 3 + (3)²
= 1 + 6 + 9
= 16
a quadratic polynomial can be formed:-
x² - (sum of zeros)x + (product of zeros)
= x² - 8x + 16 ---> required polynomial
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