Q3: If L1=(3.03 +0.02)m and L2=(2.01
+0.02)m then L1+2L2 is (in m)
O A 7.05 +0.06
OB 6.05 +0.06
Oc 6.05 +0.02
OD 7.05 +0.02
Answers
Answered by
1
Answer:
ans. (a) 7.05+0.06
explanations:
L1 = (3.03+0.02)
L2 = (2.01+0.02)
L1+2L2
so
L1 = 3.03+0.02
2L2 = 4.02+0.04
L1+2L2 = 7.05+0.06
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