Question

Q3: if sis an operation such that for integers 'a' and 'b' we have arb=axb+fax a +b). then find: (-3) = (5) ​

Answer 1

Answer:

(-3)∗(−5)

(ii) (-6)∗2

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Answer

Given, a

∗

b=a×b+(a×a+b×b)

So.

(i)

we put a=(−3) and b=(−5)

(−3)∗(−5)=(−3)×(−5)+[(−3)×(−3)+(−5)×(−5)]

=15+(9+25)=15+34=49

Answer 2

Answer:

Given, a

∗

b=a×b+(a×a+b×b)

So.

(i)

we put a=(−3) and b=(−5)

(−3)∗(−5)=(−3)×(−5)+[(−3)×(−3)+(−5)×(−5)]

=15+(9+25)=15+34=49

(ii)

Similarly, a=−6,b=2

(−6)∗2=(−6)×2+[(−6)×(−6)+2×2]

=−12+(36+4)

=−12+40=28

Step-by-step explanation:

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