Question

Q3. If the line 2x+3y+4+k(6x-y+12)=0 passes through the point (1,2), find the
value of k.​

Answer 1

Step-by-step explanation:

Here x=1 And y=2

By substituting the values,

2(1)+3(2)+4+k(6*1-2+12)=0

2+6+4+k(16)=0

12+k(16)=0

k(16)= -12

k = -12/16

k= 0.75