Question

Q3. If (x + 2) is a factor of x3 - 2mx2 + 16 then the value of mis
(a)-2
(b) 2 (c) 1
(d) - 1
Choose​

Answer 1

Answer:

x=-2, (_2) whole cube -2m(_2) whole square+16=-8-4m+16=8-4m=m=2

Answer 2

Answer:

$\boxed{\textbf{option c)1}}$

Step-by-step explanation:

$\text{(x+2) is a factor} \\ x+2=0 \\ \boxed{x = -2} \\\\ given \ polynomial, \\ p(x) =x^3-2mx^2+16 \\\\ p(-2)=0 \\\\ (-2)^3-2m(-2)^2+16=0 \\-8-2m(4)+16=0 \\-8-8m+16=0\\8m+8=16\\8m=16-8\\8m=8\\m=8/8\\ \boxed{m=1}$