Q3. If 'x' is inversely proportional to the square of 'z' and x = 3 when z= 4
Write 'x' in terms of 'z'
Find 'x' when z=5
Find 'z' when x = 12
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Step-by-step explanation:
'x' is inversely proportional to the square of 'z
=> x z^2= k
at x=3 and z = 4 => 3× 4^2= k
=> 3×16=k
=> k= 48
=> xz^2=48
=>x= 48/z^2
when z= 5=> x= 48/5^2
=> x = 48/25
when x= 12=>
z^2= 48/12=4
z = +2 or -2
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