Question

Q3. In the fig below, point O is the center of the circle. find the value of ∠ACP if ∠ POB = 90 degrees

3 points





​

Answer 1

Answer:

$Answer$

Step-by-step explanation:

(i) In circle C(O, r)

AB is the diameters.

So   ∠APB = 90˚   (Angle in semi–circle)

(ii) Now  in  △APB

∠PAB = 180˚ – (∠APB + ∠ABP)

 = 180˚ – (90˚ + 42˚)

= 180˚ – 132˚ = 48˚

∠PQB = ∠PAB = 48˚     (Angles of the same segment )

Hence

∠PQB  = 48˚

(iii) AQPB  is a cyclic quadrilateral.

$\therefore Therefore$

∠APB + ∠AQB = 180˚

⇒ 90˚ + ∠AQB = 180˚

⇒  ∠AQB = 180˚ – 90˚ = 90˚ 

HOPE THIS METHOD HELPS YOU FRIEND...

Answer 2

Answer:

Bro where is the picture.