Question

Q3. In what time will Rs 400 amount to Rs 448 at the rate of 4%
Q4. Find a number which when increased by 10% becomes 55.
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Answer 1

Step-by-step explanation:

question 3) 12days

question 4) 50

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Answer 2

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3. 3

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[Note : If the rate of interest is per annum then the time would be 3 years and if the rate is monthly, then the time would be 3 months]

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4. 50

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Sum 3 :

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Given :

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Principal (P) = ₹ 400

Rate of Interest ( r) = 4%

Time = t

Amount ( A) = 448

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We know,

$S. I. = \frac{p \: r \: t}{100}$

$A - P = \frac{p \: r \: t}{100}$

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So,

$448 - 400 = \frac{400 \times 4 \times t}{100}$

$48 = \frac{400 \times 4 \times t}{100}$

$4800 = 1600 \times t$

$t \: = \frac{4800}{1600}$

$t \: = 3$

Sum 4 :

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Let, the initial number be x

Given,

A number increased by 10% becomes 55.

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So,

x + 10% x = 55

$x \: + \frac{10}{100} x = 55$

$\frac{100x \: + \: 10x}{100} = 55$

$\frac{110x}{100} = 55$

$110x = 55 \times 100$

$110x = 5500$

$x = \frac{5500}{110}$

$x = 50$

So, the given number is 50.