Q3 l I Х f 0-2 2-4 4-6 6-8 4 8-10 10-12 2. 12-14 3 CN N 40 N find with step deviation
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Consider the following frequency distribution :
Class
0−5
6−11
12−17
18−23
24−29
Frequency
13
10
15
8
11
The upper limit of the median class is
Medium
Solution
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Correct option is B)
class frequency continuous class
0-5 13 0-5.5
6-11 10 5.5-11.5
12-17 15 11.5-17.5
18-23 8 17.5-23.5
24-29 11 23.5-29.5
Median class is the class where the (
2
n+1
)
th
term is lying.
In the given table, n=29
Therefore, (
2
n+1
)
th
value is (
2
30
)
th
=15 which lies in the class interval 12.5−17.5
The upper limit of median class is 17.5
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