q3 pls dont understand
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(3x)^2 =(cosec©)^2
9x^2=cosec^2©
now (3/x)^2=cot^2©
ie 9/x^2 =cot^2©
now apply identity
ie 9(x^2 -1/x^2)=cosec^2©-cot^2©
=1/9
9x^2=cosec^2©
now (3/x)^2=cot^2©
ie 9/x^2 =cot^2©
now apply identity
ie 9(x^2 -1/x^2)=cosec^2©-cot^2©
=1/9
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