Question

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Q3. PQ and PR are tangents to a circle with centre Alf ZQPA=27° then find ZQAR
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Answer 1

Answer:

hey mate here is your answer...

Step-by-step explanation:

ΔAQP+ΔARP

AP=APcommon

∠Q=∠R[90

∘

]

AQ=AR[radii]

So1∠QPA=∠RPA=27

∘

∠P+∠Q+∠A+∠R=360

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54+90+∠A+90=360

∘

∠A=360

∘

−180−54

∠A=180−54

∠A=126

∘

∠QAR=126

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Ans.