Question

q3: Shikha is 30

years older than her son. I year ago she was
four
times as old as her son. Find
their present ages.​

Answer 1

Answer:

$\red{\bf{\dag Age \:of\:Shikha=41\:yrs}}$

$\red{\bf{\dag Age \:of\: son=11\:yrs}}$

Step by step explanation:

→Given:

• Shikha is 30 years older than her son.
• 1 year ago she was four times as old as her son.

→To Find:

• Their present ages.

→Answer:

Let us take the present age of son be x .

Then the present age of Shikha will be (x+30) .

Now ,

• Age of Shikha 1 year ago = (x+30)-1=x+29.
• Age if son one year ago = (x-1).

Atq,

$\sf{\implies 4(x-1) = x+29}$

$\sf{\implies 4x - 4 = x + 29 }$

$\sf{\implies 4x - x = 29+4}$

$\sf{\implies 3x = 33 }$

$\sf{\implies x = \dfrac{33}{3}}$

$\bf{\leadsto x = 11 }$

Hence

• Present age of Shikha = x+30 = 11+30=41 years.
• Present age of son = x = 11 years.

Answer 2

Let , the age of son be " x "

First Condition :

Shikha is 30 years older than her son

Thus ,

Shikha's age = " x + 30 "

Second Condition :

1 year ago she was four times as old as her son

Thus ,

(x + 30 - 1) = 4(x - 1)

x + 29 = 4x - 4

33 = 3x

x = 33/3

x = 11

$\therefore$ The present ages of shikha and her son are 11 and 41