Q3 solve the following questions: 1) A man throws a ball vertically upwards with a velocity of 25m/s, assuming (g)= 10m/s. a) find the height of the ball to come back to the ground?
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1
Initial velocity of the ball final velocity =0m/s
acceleration due to gravity (g)=−10m/s
2
(upward motion)
By using the formula,
v=u+at
O=25+(−10)×t
10t=25
t=2.5sec.
The time taken for upward journey is equal to the time taken for downward journey.
Therefore, total time taken by the ball =2.5+2.5=
acceleration due to gravity (g)=−10m/s
2
(upward motion)
By using the formula,
v=u+at
O=25+(−10)×t
10t=25
t=2.5sec.
The time taken for upward journey is equal to the time taken for downward journey.
Therefore, total time taken by the ball =2.5+2.5=
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