Chemistry, asked by moichingmayumn, 2 months ago

+
Q3
The emf of the galvanic cell:
Ag/AgNO3(0.001M)//AgNO3(0.1M)/A
is : Given: E°
A -0.1182 V
B -0.8182 V
C +0.1182 V
D +0.8182 V
Ag /Ag=0.80 V​

Answers

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0

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Answered by pathakumesh99946
0

Explanation:

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