Math, asked by ansaritalib354, 3 months ago

Q3. The length of the diagonals of a rhombus are 16cm and 12cm.
Then the length of the
of the sides of the shombus. :
ca
(b) 10cm
(Bom
U 20 cm
9 cm​

Answers

Answered by rakeshkushwaha379057
0

Answer:

Let ABCD be the rhombus and AC and BD bisect at point O. AC = 16cm and BD = 12cm.

⇒ We know that the diagonals of rhombus bisect at right angles.

⇒ AO=

2

16

=8cm

⇒ BO=

2

12

=6cm

⇒ In right angled △AOB,

By using Pythagoras theorem,

⇒ AB

2

=AO

2

+BO

2

⇒ AB

2

=8

2

+6

2

⇒ AB

2

=64+36

⇒ AB

2

=100

⇒ AB=

100

⇒ AB=10cm

∴ Side of a rhombus is 10cm.

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