Question

Q3. The perimeter of a rectangle is 70 cm. If its length excecu
by 5cm. Find the dimensions of the rectangle.​

Answer 1

Answer:

The Breadth of the Rectangle is 15 cm and Length is 20 cm.

Step-by-step explanation:

Given :

Perimeter = 70 cm

Length = Exceeds breadth by 5 cm

To find :

The Rectangle's dimensions

Solution :

Let The :

• Breadth be y
• Length be (y + 5)

★ $\textsf{\underline{\underline{Dimensions of the rectangle :}}}$

$\sf{Perimeter = \purple{2(Length+Breadth)}}$

$\sf{\implies} \: 2( y + 5 + y) = 70 \\ \\ \sf{\implies} \: 2(2y + 5) = 70 \\ \\ \sf{\implies} \: 4y + 10 = 70 \\ \\ \sf{\implies} \: 4y = 70 - 10 \\ \\ \sf{\implies} \: 4y = 60 \\ \\ \sf{\implies} \: y = \dfrac{60}{4} \\ \\ \sf{\implies} \: y = 15$

Breadth = 15 cm

$\rule{300}{1.5}$

★ $\textsf{\underline{\underline{Length of the rectangle :}}}$

$\sf{\implies} \: y + 5 \\ \\ \sf{\implies} \: 15 + 5 \\ \\ \sf{\implies} \: 20$

Length = 20 cm

$\therefore$ The Breadth of the Rectangle is 15 cm and Length is 20 cm.

Answer 2

Question :

The perimeter of a rectangle is 70 cm. If its length exceed breadth by 5cm. Find the dimensions of the rectangle.

Solution :

$\underline{\bold {Given:}}$

• The perimeter of the rectangle=70 cm

$\underline{\bold {To\:Find:}}$

• The dimensions of the rectangle.

$\rule {193}{1}$

Let the breadth of the rectangle be x cm.

Then,its length =(x+5) cm

$\fbox {\purple {Perimeter\: of\: rectangle=2 (length + breadth)}}$

$\implies Perimeter\: of\:the \: rectangle=2 (length + breadth) \\ \implies 70 \:=2 (x + 5 +x) \\ \implies 70= 2(2x + 5) \\ \implies 70 = 4x + 10 \\ \implies70 - 10 = 4x \\ \implies 60 = 4x \\ \implies \frac{60}{4} = x \\ \implies 15 = x \\ \implies x = 15$

$\boxed{\green{\therefore{Length\:of\: the\: rectangle=(15+5)\:cm=20\:cm}}}$

$\boxed{\green{\therefore{Breadth \:of the\: rectangle=15\:cm}}}$