Q3.The perimeter of a square is 68m. The perimeter of a rectangle is double the
perimeter of a square. The width of a rectangle is 10m more than the side of the
square. The difference of area(in m square) of rectangle and square is:--
8219
O
818
289
O 1107
Answers
Given:
Perimeter of the square = 68 m
Perimeter of the rectangle = double of the perimeter of square
Width of the rectangle = Width of the square + 10m
To find:
The difference of area of rectangle and square (in m^2).
Solution:
The perimeter of square = 68m
Perimeter of square= sum of all sides
Therefore the length of each side of square a = perimeter/4
= 68/4 = 17 m
Perimeter of rectangle= 2*(l+b)
As given perimeter of rectangle= 2* perimeter of square
Perimeter of rectangle= 2*68 = 136 m
Therefore 2(l+b) = 136
Where l is the length and b the breadth of rectangle.
Width of rectangle b = a+10
b= 17+10 = 27 m
Therefore 2(l + 27) = 136
l + 27 = 68
l = 41m
Area of square = a^2 = 17^2 = 289 m^2
Area of rectangle = l*b = 41*27 = 1107 m^2
Difference on area = 1107 - 289 m^2 = 818 m^2
The answer is 818 m^2.
Answer:
The difference of area of rectangle and square (in m^2). Where l is the length and b the breadth of rectangle. The answer is 818 m^2.