Question

Q3)The sum of the digits of a two digit number is 5 .If the digits are reversed, the number is
reduced by 27.Find the number.
(3)​

Answer 1

5 is 27 is number is
$X2 12-3 X2 144-9 X2 135 X 13$

Answer 2

Solution :

Let the digit at unit's place be x and the digit at ten's place y.

=> Required no. = 10y + x

If the digit's are reversed,

=> Reversed no. = 10y + x

According to the question,

=> x + y = 5...(1)

and,

=> (10y + x) - (10x + y)= 27

=> 9y - 9x = 27

=> y - x = 3.... (2)

Now adding the two equation,

y - x =3

y + x =5

-------------

2y = 8

y = 8/2

y = 4

From (1)

=> x + 4 = 5

=> x = 1

Require no is

=> 10(4) + 1

=> 41

=> Required number is 41