Question

Q3) The x and y components of a force vector Fare 3 N and 4 N respectively, find the
magnitude and direction of F.
Q4) A force is applied perpendicularly on a door 4 meters wide which requires a torque of
120Nm to open it. What will be the minimum force required?​

Answer 1

Answer:

4. in physics how much talk you you exert on an object depends on two things before you x80f and deliver on also called the moment on the lever arm is the perpendicular distance from the pivot point to the point at which you assert your force and is related to the distance from the axis are r by.

Answer 2

Answer:

ans 3. the required force will 3i + 4j and hence the magnitude will be ( 3^2 + 4^2)^1/2 = 5

ans 4.. Torque = r × F

120 = 4 × F

F = 30 N