Question

Q3.two pencils are 24cm and 42cm long. if we have to make them of equal size, then the minimum number of similar pencils is

Answer 1

Answer:Let's take hcf of 24 and 42=6

Divide 24 by 6 and 42 respectively we will get 4and 7equal divisions.

Total equal division will be 7+4=11

Step-by-step explanation:

Answer 2

The minimum number of similar pencils is seven.

Step-by-step explanation:

The lengths of the two pencils are 24 cm and 42 cm.

To find the minimum number of similar pencils, we need to find a number that can divide both 24 and 42 (highest common factor, HCF)

Factors of 24 are 2,2,2,3.

Factors of 42 are 2,3,7.

So, the highest common factor is 2 times 3 = 6.

Hence, the pencil with a length of 24 cm can be divided into four pencils of length 6 cm.

And the pencil with a length of 42 cm can be divided into seven pencils of length 6 cm.

Total number of pencils = 4 + 7 = 11.