Question

Q3.
Velocity of a train changes from 20ms^-1 to 25 ms^-1 , when it accelerates as
of 2ms^-2. Find the distance covered by the train.​

Answer 1

u = 20m/s²

v = 15m/s²

a = 2m/s²

From the equation,

v²=u²+2as

=> 25²=20²+2×2s

=> 625 = 400 +4s

=>625-400 = 4s

=>225 = 4s

=>s = 56.25m

Distance covered by train = 56.25m.

Cheers!

Answer 2

Use the formula V^2=U^2-2as
here V=25,U=20 and a=2
by substituting, we get 
25*25=20*20+2*2*s
625-400=4s
225/4=s 
hence the distance covered is 225/4