Question

Q3 verify whether the indicated numbers are
zeroes of the polynomial g(x)= 3x² -2, x=2/3 and -2/3

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Answer 1

Step-by-step explanation:

3x^2 - 2 = 0

x^2 = 2/3

x = ±√2/√3

the given numbers are not the zeroes of the polynomial g(x) .

hope you get that ✌

Answer 2

Step-by-step explanation:

g(x) = 3x²- 2

$g(x) = 3 \times {(\frac{2}{3 \: } )} ^{2} - 2$

$g( \frac{2}{3} ) = 3 \times \frac{4}{9} - 2$

$g( \frac{2}{3} ) = \frac{4}{3} - 2$

TAKE LCM..

$g( \frac{2}{3} ) = \frac{4}{3} - \frac{6}{3}$

$g( \frac{2}{3} ) = \frac{ - 2}{3}$

$\frac{2}{3} \: \:is \: not \: a \:zero \: of \: this \: polynomial$

$g( \frac{ - 2}{3} ) = 3 \times {( \frac{ - 2}{3} )} ^{2} - 2$

-2/3 is also not zero of this polynomial!