Q3. What is observed when a solution of potassium iodide is added to a solution of lead nitrate?Write a balanced chemical equation to represent the above chemical reaction.
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Observation : KNO3 along with a yellow precipitate of PbI2 is formed.
Balanced equation :
Pb(NO3)2 + 2KI ---------> 2KNO3 + PbI2
Balanced equation :
Pb(NO3)2 + 2KI ---------> 2KNO3 + PbI2
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Answer:
◆ When a solution of potassium iodide is added to a solution of lead nitrate taken in a test tube, the precipitation of a yellowish solid is observed. This yellowish solid is lead iodide. Potassium nitrate is formed along with lead iodide.
◆ This is a double displacement reaction.
◆ When the two ionic compounds / elements exchange their ions is called Double Displacement Reaction.
◆ The balanced chemical equation for the above reaction is:
Balanced Equation: Pb(NO3)2 + 2KI --- 2KNO3 + PbI2
Word Equation: lead nitrate + Potassium Iodide ---- Potassium Nitrate + Lead Iodide.
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