Question

Q3. 〖〖(x〗^2+1) 〗^2-x²=0 has 1.four real roots 2.two real roots 3. no real roots 4.one real root

Answer 1

Answer:

A quadratic equation, ax2 + bx + c = 0; a ≠ 0 will have two distinct real roots if its discriminant, D = b2 - 4ac > 0. Hence, the equation x2 –3x + 4 = 0 has no real roots. Hence, the equation 2x2 + x – 1 = 0 has two distinct real roots.