Q30. The angle of elevation of the top of a hill at the foot of a tower is 60° and the angle of depression
from the top of the tower to the foot of the hill is 30°. If the tower is 50 m high, find the height of the
hill.
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tan 30° = height of tower / distance between them
1/√3 = 50 / d
d = 50√3 m --------(i)
tan 60° = height of hill / distance between them
√3 = h / 50√3 ----- [ from (i) ]
√3 × 50√3 = h
h = 50 × 3
h = 150 m
Answer: 150 meters
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