Question

Q32)A garden in the shape of
a rhombus. The perimeter of
the garden is 40m and its
diagnol is 16 m. It is to be
divide into two equal parts
and use these parts in
rotation. Then the area of
each part of the garden is *​

Answer 1

Answer:

Perimeter of the garden=40m

Length of each side of the rhombus=(40/4)m=10m

let length of the 2nd diagonal be x m

∴ a=÷2 (a:length of side, m:length of first                                                                          diagonal, n:length of second diagonal)

=>2×10=

=>(20)²=256+n²

=>400=256+n²

=>n²=400-256=144

=>n=12m

Length of second diagonal=12m

Area of the garden=(m×n)÷2

                            =(16×12)÷2

                            =96m²

Area of each part of garden=(96÷2)=48m²

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

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