Question

Q32.
One of the factors of (1 + 3y)2 + (9y2 – 1) is
A
1-3y
8
3- y
с
3y + 1
D
y-3​

Answer 1

Answer:

First notice that (9y squared -1) is the difference of two squares and equals

(3y-1)(3y +1)

So we can rewrite the equation as

(1+3y)+(1+3y)(1–3y)

Factor out the (1+3y)

(1+3y)(1+(1–3y))

The ones cancel so

(1+3y)(3y)

And done