Question

Q32. Prove that Equal chords of a congruent circles subtend equal angles at their centres​

Answer 1

Answer:

In △AOB and △PXQ

AO=PX [Radius of congruent circles are equal]

∠AOB=∠PXQ [Given]

BO=QX [Radius of congruent circles are equal]

△AOB≅△PXQ [SAS congruence rule]

∴AB=PQ [CPCT]