Question

Q33. The sum of three consecutive integers is 5 more than the smallest of the integers. Find the integers.​

Answer 1

Given:

• The sum of three consecutive integers is 5 more than the smallest of the integers.

To find:

• The integers

Solution:

❐ Let the three consecutive integers be a, (a + 1) & (a + 2).

ATQ,

➯ a + a + 1 + a + 2 = a + 5

➯ 3a + 3 = a + 5

➯ 3a - a = 5 - 3

➯ 2a = 2

➯ a = 2/2

➯ a = 1

Hence,

• First Consecutive integer = a = 1
• Second Consecutive integer = (a + 1) = 2
• Third Consecutive integer = (a + 2) = 3

━━━━━━━━━━━

Answer 2

Answer:

$\huge\bold\purple{xXMarathiGirlXx}$